2 f ( 0 ) = 2 ( sin ( 60 ∘ ) ) = 2 ( 3 2 ) = 2 3 2 = 3 {\displaystyle 2f(0)=2(\sin(60^{\circ }))=2({\frac {\sqrt {3}}{2}})={\frac {{\cancel {2}}{\sqrt {3}}}{\cancel {2}}}={\sqrt {3}}}
