5.5 The Substitution Rule/59: Revision history

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6 September 2022

  • curprev 01:5801:58, 6 September 2022‎ Elizabethh58413 talk contribs‎ 577 bytes +577‎ Created page with "<math> \int_{1}^{2}\frac{ e^\frac{1}{x}}{x^2}\,dx </math> <br><br> <math> \begin{align} u &=\frac{1}{x} \\[2ex] du &=-\frac{1}{x^2}dx \\[2ex] -du &=\frac{1}{x^2}dx \\[2ex] \end{align} </math> New upper limit:<math> \frac{1}{2} = \frac{1}{(2)} <\math> <br> New lower limit: <math> 1 = \frac{1}{(1)} <\math> <math> \begin{align} \int_{1}^{2}\frac{ e^\frac{1}{x}}{x^2}\,dx &=\int_{1}^{2} e^\frac{1}{x}(\frac{1}{x^2}\,dx) &=\int_{1}^{\frac{1}{2}}e^u\,-du \\[2ex] &=-\int_{1}..."
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