5.3 The Fundamental Theorem of Calculus/10: Difference between revisions

Revision as of 19:07, 25 August 2022

$g(r)=\int _{0}^{r}{\sqrt {x^{2}+4}}dx$

${\frac {d}{dx}}$

Revision as of 19:05, 25 August 2022 (view source) Andy Arevalo (talk \| contribs) No edit summary ← Older edit		Revision as of 19:07, 25 August 2022 (view source) Andy Arevalo (talk \| contribs) No edit summary Newer edit →
Line 1:		Line 1:
	<math> g(r)=\int_{0}^{r}\sqrt{x^2+4} dx </math> <br><br>		<math> g(r)=\int_{0}^{r}\sqrt{x^2+4} dx </math> <br><br>
	<math>\frac{d}{dx}<math>		<math>\frac{d}{dx}</math>