5.3 The Fundamental Theorem of Calculus/23: Difference between revisions
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&\cfrac{5 \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex] | &\cfrac{5 \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex] | ||
& | &\cfrac{5 \sqrt[1^5]{1^4}}{9} | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 19:13, 25 August 2022
![{\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&{\cfrac {5{\sqrt[{5}]{x^{4}}}}{9}}\\[2ex]&{\cfrac {5{\sqrt[{5}]{x^{4}}}}{9}}{\bigg |}_{0}^{1}\\[2ex]&{\cfrac {5{\sqrt[{1^{5}}]{1^{4}}}}{9}}\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/3911c060baff8e41cb3726ec08433cabf1f3b342)