5.3 The Fundamental Theorem of Calculus/15: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 4: | Line 4: | ||
<math> | <math> | ||
\begin{align} | \begin{align} | ||
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\ | y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec^{2]</math> | ||
Revision as of 19:14, 25 August 2022
Use part 1 of the FTC to find the derivative of the function:
Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec^{2]}