5.3 The Fundamental Theorem of Calculus/15: Difference between revisions
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\begin{align} | \begin{align} | ||
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec | |||
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec</math> | |||
Revision as of 19:14, 25 August 2022
Use part 1 of the FTC to find the derivative of the function:
Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec}