5.3 The Fundamental Theorem of Calculus/15: Difference between revisions

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<math>
<math>
\begin{align}
\begin{align}
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec^{2]</math>
 
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec</math>

Revision as of 19:14, 25 August 2022

Use part 1 of the FTC to find the derivative of the function:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt =\sec}