5.3 The Fundamental Theorem of Calculus/15: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 5: | Line 5: | ||
\begin{align} | \begin{align} | ||
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt =\sec^{2}(x)·\sqrt | y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt =\sec^{2}(x)·{\sqrt\tan{x+\tan(x)} | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 19:20, 25 August 2022
Use part 1 of the FTC to find the derivative of the function:
Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt =\sec^{2}(x)·{\sqrt\tan{x+\tan(x)} \end{align} }