5.3 The Fundamental Theorem of Calculus/15: Difference between revisions
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Use part 1 of the FTC to find the derivative of the function: | Use part 1 of the FTC to find the derivative of the function: | ||
<math>y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t} dt</math> | <math>y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt</math> | ||
<math> | <math> | ||
\begin{align} | \begin{align} | ||
y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt =\sec^{2}(x)· | y=\int_{0}^{tan(x)}\sqrt{t+\sqrt t}\,dt =\sec^{2}(x)· | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 19:21, 25 August 2022
Use part 1 of the FTC to find the derivative of the function:
