5.3 The Fundamental Theorem of Calculus/19: Difference between revisions

Revision as of 19:21, 25 August 2022

${\begin{aligned}\int \limits _{-1}^{2}(x^{3}-2x)dx&={\frac {x^{4}}{4}}-{\frac {2x^{2}}{2}}{\bigg |}_{-1}^{2}\end{aligned}}$

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	<math>\begin{align}\int\limits_{-1}^{2}(x^3-2x) dx~~</math>~~&=\frac{x^4}{4}-\frac{2x^2}{2}\bigg\|_{-1}^{2}\end{align}</math>		<math>\begin{align}\int\limits_{-1}^{2}(x^3-2x)dx&=\frac{x^4}{4}-\frac{2x^2}{2}\bigg\|_{-1}^{2}\end{align}</math>