5.3 The Fundamental Theorem of Calculus/35: Difference between revisions

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\begin{align}
\begin{align}


\int_{1}^{9}\frac{1}{2x}dx = \frac{1}{2}\int_{1}^{9}\frac{1}{x}dx = \frac{1}{2}\ln{|x|}\bigg|_{1}^{9}
\int_{1}^{9}\frac{1}{2x}dx = \frac{1}{2}\int_{1}^{9}\frac{1}{x}dx =  
\frac{1}{2}\ln{|x|}\bigg|_{1}^{9} = \frac{1}{2}\ln{|9|}-frac{1}{2}\ln{|1|}=
\ln{|9|}




\end {align}
\end {align}
</math>
</math>

Revision as of 19:25, 25 August 2022