5.3 The Fundamental Theorem of Calculus/7: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 1: | Line 1: | ||
<math>g(x)=\int_{1}^{x}\frac{1}{t^3+1}dt</math><br> | <math>g(x)=\int_{1}^{x}\frac{1}{t^3+1}dt</math><br> | ||
<math>\frac{d}{dx}\left[g(x)\right]=\frac{d}{dx}\left[\int_{1}^{x}\frac{1}{t^3+1}dt\right]</math> | <math>\frac{d}{dx}\left[g(x)\right]=\frac{d}{dx}\left[\int_{1}^{x}\frac{1}{t^3+1}dt\right]</math>=(1)\left(\frac{1}{1+x^3}\right)</math> | ||
(1)\left(\frac{1}{1+x^3}\right)</math> | |||
Revision as of 19:37, 25 August 2022
=(1)\left(\frac{1}{1+x^3}\right)</math>
![{\displaystyle {\frac {d}{dx}}\left[g(x)\right]={\frac {d}{dx}}\left[\int _{1}^{x}{\frac {1}{t^{3}+1}}dt\right]}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/f940df279b1920a77a743c787af515d9035eeeea)