5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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<math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math> | <math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math> | ||
<math>h'(x)=\-frac{1}{x^2} | <math>h'(x)=\-frac{1}{x^2}</math> | ||
Revision as of 19:38, 25 August 2022
Failed to parse (syntax error): {\displaystyle h'(x)=\-frac{1}{x^2}}