5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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<math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math> | <math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math> | ||
<math>h'(x)=\frac{-1}{x^2}(arctan(\frac{1}{x})-0</math> | <math>h'(x)=\frac{-1}{x^2}\left(\arctan(\frac{1}{x}\right)-0</math> | ||
Revision as of 19:47, 25 August 2022
