5.3 The Fundamental Theorem of Calculus/13: Difference between revisions

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<math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math>
<math>h(x)=\int_{2}^{1/x}\arctan(t)dt</math>


<math>\frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[\int_{2}^{1/x}\arctan(t)dt\right]</math>
<math>\frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[\int_{2}^{1/x}\arctan(t)dt\right]=\frac{d}{dx}</math>

Revision as of 19:57, 25 August 2022