5.3 The Fundamental Theorem of Calculus/41: Difference between revisions
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<math> = \int\limits_{0}^{\frac{\pi}{2}}f(x)dx + \int\limits_{\frac{\pi}{2}}^{\pi}f(x)dx = \int\limits_{0}^{\frac{\pi}{2}}\sin(x)dx + \int\limits_{\frac{\ | <math> = \int\limits_{0}^{\frac{\pi}{2}}f(x)dx + \int\limits_{\frac{\pi}{2}}^{\pi}f(x)dx = \int\limits_{0}^{\frac{\pi}{2}}\sin(x)dx + \int\limits_{\frac{\ | ||
\pi}{2}}^{\pi}\cos(x)dx | {\pi}{2}}^{\pi}\cos(x)dx | ||
</math> | </math> |
Revision as of 20:04, 25 August 2022
Failed to parse (syntax error): {\displaystyle = \int\limits_{0}^{\frac{\pi}{2}}f(x)dx + \int\limits_{\frac{\pi}{2}}^{\pi}f(x)dx = \int\limits_{0}^{\frac{\pi}{2}}\sin(x)dx + \int\limits_{\frac{\ {\pi}{2}}^{\pi}\cos(x)dx }