6.2 Trigonometric Functions: Unit Circle Approach/53: Difference between revisions
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\sin{\left(\frac{8\pi}{3}\right)} &= \frac{\sqrt{3}}{2} & \csc{\left(\frac{8\pi}{3}\right)} &= \frac{2}{1}=2\\[2ex] | \sin{\left(\frac{8\pi}{3}\right)} &= \frac{\sqrt{3}}{2} & \csc{\left(\frac{8\pi}{3}\right)} &= \frac{2}{1}=2\\[2ex] | ||
\cos{\left(\frac{8\pi}{3}\right)} &= \frac{ | \cos{\left(\frac{8\pi}{3}\right)} &= -\frac{1}{2} & \sec{\left(\frac{8\pi}{3}\right)} &= \frac{{2}}{-\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = -\frac{2\sqrt{3}}{3}\\[2ex] | ||
\tan{\left(\frac{8\pi}{3}\right)} &= \frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2}} = \left(\frac{1}{2}\right)\left(-\frac{2}{\sqrt{3}}\right) = -\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = -\frac{\sqrt{3}}{3} | \tan{\left(\frac{8\pi}{3}\right)} &= \frac{\frac{1}{2}}{-\frac{\sqrt{3}}{2}} = \left(\frac{1}{2}\right)\left(-\frac{2}{\sqrt{3}}\right) = -\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}} = -\frac{\sqrt{3}}{3} | ||
& \cot{\left(\frac{8\pi}{3}\right)} &= -\frac{\sqrt{3}}{1}= -\sqrt{3} \\[2ex] \end{align} </math> | & \cot{\left(\frac{8\pi}{3}\right)} &= -\frac{\sqrt{3}}{1}= -\sqrt{3} \\[2ex] \end{align} </math> |
Revision as of 03:44, 26 August 2022