5.4 Indefinite Integrals and the Net Change Theorem/29: Difference between revisions

Revision as of 16:15, 26 August 2022

$\int \limits _{2}^{-1}\left(4y^{3}{\frac {2}{y^{3}}}\right)dy$
$y^{4}-y^{-}2{\bigg |}_{-2}^{-1}=(1-1)-(16-1/4)=-63/4$

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-<math>\int\limits_{2}^{-1}\left(4y^3+\left(\frac{2}{y^3}\right)\right)dy</math><br>
+<math>\int\limits_{2}^{-1}\left(4y^3\frac{2}{y^3}\right)dy</math><br>
 <math>y^4-y^-2\bigg|_{-2}^{-1}=(1-1)-(16-1/4)=-63/4
 </math>