6.2 Trigonometric Functions: Unit Circle Approach/35: Difference between revisions

Revision as of 17:13, 26 August 2022

$\sin {(45^{\circ })}\cos {(45^{\circ })}={\frac {{\sqrt {2}}{2}}{\cdot }}{\frac {\sqrt {2}}{=}}$

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	<math>\sin{(45^\circ)}\cos{(45^\circ)}= \frac{\sqrt{2}}{2}}\cdot\frac{\sqrt{2}}=</math>		<math>\sin{(45^\circ)}\cos{(45^\circ)}= \frac{\sqrt{2}{2}}\cdot\frac{\sqrt{2}}=</math>