6.2 Trigonometric Functions: Unit Circle Approach/98: Difference between revisions

Latest revision as of 17:16, 26 August 2022

$f(\theta )=\sin(\theta )$
$g(\theta )=\cos {(\theta )}$
$\theta =60^{\circ }$

$g\left({\frac {\theta }{2}}\right)=g\left({\frac {60^{\circ }}{2}}\right)=g(30^{\circ })=\cos(30^{\circ })={\frac {\sqrt {3}}{2}}$

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-<math> \text{If } f(\theta)=\sin(\theta) \text{, } g(\theta)=\cos{\theta} \text{ and } \theta = 60^{\circ} \text{ then } g(\left(\frac{\theta}{2}\right)</math>
+<math> f(\theta)=\sin(\theta)</math> <br>
+<math> g(\theta)=\cos{(\theta)}</math> <br>
+<math> \theta = 60^{\circ}</math> <br><br>
+<math> g\left(\frac{\theta}{2}\right)=g\left(\frac{60^{\circ}}{2}\right) = g(30^{\circ}) = \cos(30^{\circ}) = \frac{\sqrt{3}}{2}</math>