5.4 Indefinite Integrals and the Net Change Theorem/30: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 7: Line 7:
&= \left(\frac{y^{-2+1}}{-2+1}+\frac{5y^{4+1}}{4+1}\right)\bigg|_{1}^{2} = \left(\frac{y^{-1}}{-1}+y^5\right)\bigg|_{1}^{2} = \left(-\frac{1}{y}+y^5\right)\bigg|_{1}^{2} \\[2ex]
&= \left(\frac{y^{-2+1}}{-2+1}+\frac{5y^{4+1}}{4+1}\right)\bigg|_{1}^{2} = \left(\frac{y^{-1}}{-1}+y^5\right)\bigg|_{1}^{2} = \left(-\frac{1}{y}+y^5\right)\bigg|_{1}^{2} \\[2ex]


&= \left(-\frac{1}{(2)}+(2)^5\right) - \left(-\frac{1}{(1)}+(1)^5\right)  
&= \left(-\frac{1}{(2)}+(2)^5\right) - \left(-\frac{1}{(1)}+(1)^5\right) \\[2ex]


&= \left(-\frac{1}{2}+32\right)
&= \left(-\frac{1}{2}+32\right)
\end{align}
\end{align}
</math>
</math>

Revision as of 18:15, 26 August 2022