5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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=<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math> | =<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math> | ||
=<math>\1y+\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math> | =<math>\1y+\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math> | ||
Revision as of 18:55, 26 August 2022
= =Failed to parse (syntax error): {\displaystyle \1y+\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}}
