5.3 The Fundamental Theorem of Calculus/33: Difference between revisions

Revision as of 18:56, 26 August 2022

$\int _{1}^{2}\left(1+2y^{2}\right)dy$ = $\int _{1}^{2}\left(4y^{2}+4y+1\right)dy$ = ${\frac {4y^{3}}{3}}+{\frac {4y^{2}}{2}}{\bigg |}_{1}^{2}$

@@ Line 1: / Line 1: @@
 <math>\int_{1}^{2}\left(1+2y^2\right)dy</math>
 =<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math>
-=<math>\+\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math>
+=<math>\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math>