5.3 The Fundamental Theorem of Calculus/33: Difference between revisions

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=<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math>
=<math>\int_{1}^{2}\left(4y^2+4y+1\right)dy</math>
=<math>\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math>
=<math>\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2}</math>
=<math>2 +frac{32}{3}</math>
=<math>2\left(\frac{32}{3}\</math>
<math>2\left(\frac{32}{3}\</math>

Revision as of 19:00, 26 August 2022

= = =Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle 2\left(\frac{32}{3}\}