6.2 Trigonometric Functions: Unit Circle Approach/15: Difference between revisions
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(Created page with ":<math> \begin{align} -\frac{2}{5},\frac\sqrt{21}{5} \sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex] \cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex] \tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex] \end{align} </math> \end{align} </math>") |
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\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex] | \sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex] | ||
\cos{(t)} &= \frac | \cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex] | ||
\tan{(t)} &= \frac{ | \tan{(t)} &= \frac\sqrt-{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex] | ||
\end{align} | \end{align} | ||
Revision as of 18:53, 30 August 2022
![{\displaystyle {\begin{aligned}-{\frac {2}{5}},{\frac {\sqrt {21}}{5}}\sin {(t)}&={\frac {\sqrt {21}}{5}}&\csc {(t)}&={\frac {r}{y}}\\[2ex]\cos {(t)}&=-{\frac {2}{5}}&\sec {(t)}&={\frac {r}{x}}\\[2ex]\tan {(t)}&={\frac {\sqrt {-}}{21}}{2}&\cot {(t)}&={\frac {x}{y}}\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/06ef5b33a68c0fbb93318b79869cba2d5416ac69)
\end{align}
</math>