6.2 Trigonometric Functions: Unit Circle Approach/15: Difference between revisions
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(Created page with ":<math> \begin{align} -\frac{2}{5},\frac\sqrt{21}{5} \sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{r}{y}\\[2ex] \cos{(t)} &= \frac\{x}{r} & \sec{(t)} &= \frac{r}{x}\\[2ex] \tan{(t)} &= \frac{y}{x} & \cot{(t)} &= \frac{x}{y} \\[2ex] \end{align} </math> \end{align} </math>") |
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\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{ | \sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{5\sqrt{21}}{21}\\[2ex] | ||
\cos{(t)} &= \frac | |||
\tan{(t)} &= \frac{ | \cos{(t)}&= -\frac{2}{5} & \sec{(t)} &= \frac{5}{-2}\\[2ex] | ||
\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &=\frac{2\sqrt{21}}{21} \\[2ex] | |||
\end{align} | \end{align} | ||
Latest revision as of 19:29, 30 August 2022
![{\displaystyle {\begin{aligned}-{\frac {2}{5}},{\frac {\sqrt {21}}{5}}\sin {(t)}&={\frac {\sqrt {21}}{5}}&\csc {(t)}&={\frac {5{\sqrt {21}}}{21}}\\[2ex]\cos {(t)}&=-{\frac {2}{5}}&\sec {(t)}&={\frac {5}{-2}}\\[2ex]\tan {(t)}&=-{\frac {\sqrt {21}}{2}}&\cot {(t)}&={\frac {2{\sqrt {21}}}{21}}\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/846dbe168f93cb284503d556b19e7d1469420648)
\end{align}
</math>