David: Difference between revisions
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<math>f(x)=x^3+\frac{1}{2}x^2+x-5</math> | <math>f(x)=x^3+\frac{1}{2}x^2+x-5</math> | ||
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Revision as of 21:12, 30 August 2022
Hi my name is David..
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