David: Difference between revisions

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| <math>f(x)=x^3+\frac{1}{2}x^2+x-5</math>
| <math>f(x)=x^3+\frac{1}{2}x^2+x-5</math>
| Data 2
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Revision as of 21:14, 30 August 2022

Hi my name is David..


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