5.4 Indefinite Integrals and the Net Change Theorem/41: Difference between revisions

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<math>\int_{0}^\frac{1}\sqrt{3}\frac{t^2-1}{t^4-1} dt
<math>\begin{align}\int_{0}^\frac{1}\sqrt{3}\frac{t^2-1}{t^4-1} dt=\int_{0}^\frac{1}\sqrt{3} \frac{(t^2-1)}{(t^2-1))(t^2+1)} dt
</math>
\end{align}</math>

Revision as of 20:03, 1 September 2022