5.5 The Substitution Rule/15: Difference between revisions

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Line 6: Line 6:
\begin{align}
\begin{align}


let u &=\pi t \\[2ex]
let \hspace u &=\pi t \\[2ex]
du &= \pi dx \\[2ex]
du &= \pi dx \\[2ex]
\frac{1}{\pi}du &= dx
\frac{1}{\pi}du &= dx

Revision as of 04:36, 5 September 2022

Failed to parse (unknown function "\hspace"): {\displaystyle \begin{align} let \hspace u &=\pi t \\[2ex] du &= \pi dx \\[2ex] \frac{1}{\pi}du &= dx \end{align} }