6.2 Trigonometric Functions: Unit Circle Approach/61: Difference between revisions

Latest revision as of 17:22, 6 September 2022

${\frac {5\pi }{6}}$

$\sin({\frac {5\pi }{6}})=1$

$\sec({\frac {5\pi }{6}})={\frac {1}{1}}=1$

$\cos({\frac {5\pi }{6}})=0$

$\csc({\frac {5\pi }{6}})={\frac {1}{0}}=Undefined$

$\tan({\frac {5\pi }{6}})={\frac {1}{0}}=Undefind$

$\cot({\frac {5\pi }{6}})={\frac {0}{1}}=0$

@@ Line 1: / Line 1: @@
 <math> \frac{5\pi}{6}
-\sin({\frac{5\pi}{6}})=1 \sec({\frac{5\pi}{6}})=\frac{1}{1}=1
+</math>
-\cos({\frac{5\pi}{6}})=0 \csc({\frac{5\pi}{6}})=\frac{1}{0}=Undefined
-\tan({\frac{5\pi}{6}})=\frac{1}{0}=Undefind \cot({\frac{5\pi}{6}})=\frac{0}{1}=0
+<math>
+\sin({\frac{5\pi}{6}})=1
+</math>
+<math>
+ \sec({\frac{5\pi}{6}})=\frac{1}{1}=1
+</math>
+<math>
+\cos({\frac{5\pi}{6}})=0
+</math>
+<math>
+\csc({\frac{5\pi}{6}})=\frac{1}{0}=Undefined
+</math>
+<math>
+\tan({\frac{5\pi}{6}})=\frac{1}{0}=Undefind
+</math>
+<math>
+\cot({\frac{5\pi}{6}})=\frac{0}{1}=0
 </math>