6.2 Trigonometric Functions: Unit Circle Approach/41: Difference between revisions

Revision as of 17:54, 6 September 2022

$2(\sin({\frac {\pi }{3}}))-3(\tan({\frac {\pi }{6}}))$

$2({\frac {\sqrt {3}}{2}})-3({\frac {\frac {1}{\cancel {2}}}{\frac {\sqrt {3}}{\cancel {2}}}})$

$2({\frac {\sqrt {3}}{2}})-3({\frac {1}{\sqrt {3}}})$

$/frac{2{\sqrt {3}}}{2}-{\frac {3}{\sqrt {3}}}$

@@ Line 1: / Line 1: @@
 <math>2(\sin(\frac{\pi}{3}))-3(\tan(\frac{\pi}{6}))</math>
-<math>2(\frac{\sqrt{3}}{2})-3(\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}})
+<math>2(\frac{\sqrt{3}}{2})-3(\frac{\frac{1}{\cancel{2}}}{\frac{\sqrt{3}}{\cancel{2}}})
+</math>
+<math>
+(\frac{\sqrt{3}}{2})-3(\frac{1}{\sqrt{3}})
+</math>
+<math>
+/frac{2\sqrt{3}}{2}-\frac{3}{\sqrt{3}}
 </math>