5.3 The Fundamental Theorem of Calculus/9: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
m (Protected "5.3 The Fundamental Theorem of Calculus/9" ([Edit=Allow only administrators] (indefinite) [Move=Allow only administrators] (indefinite)))
 
(38 intermediate revisions by 3 users not shown)
Line 1: Line 1:
<math>\begin{align}
<math>g(y)= \int_{2}^{y}t^2\sin{(t)}dt</math><br><br>
g(y)&= \int_{y}^{2}t^2\sin{(t)}dt \\[2ex]
 
&= 1(y^{2}sin{(y)})-0(2^{2}sin{(2)})\\[2ex]
<math>
&= y^{2} sin{(y)} \\[2ex]
 
\end(align)</math>
\frac{d}{dy}\left[g(y)\right] = \frac{d}{dy}\left[\int_{2}^{y}t^2\sin{(t)}dt\right]
 
= 1\cdot((y)^{2}\sin{y})-0\cdot((0)^{2}\sin{(2)})
= y^{2}\sin{(y)}
 
</math>
 
 
<math>
\text{Therefore, } g'(y) = y^{2}\sin{(y)}
</math>

Latest revision as of 20:14, 6 September 2022