5.3 The Fundamental Theorem of Calculus/23: Difference between revisions
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&\int_{0}^{1}x^\ | &\int_{0}^{1}x^{\frac{4}{5}}dx \\[2ex] | ||
Revision as of 20:41, 6 September 2022
![{\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\frac {4}{5}}dx\\[2ex]&{\cfrac {5\cdot {\sqrt[{5}]{x^{4}}}}{9}}{\bigg |}_{0}^{1}\\[2ex]&{\cfrac {5\cdot {\sqrt {1^{4}}}}{9}}-{\cfrac {5{\sqrt[{5}]{0^{4}}}}{9}}\\[2ex]&={\cfrac {5}{9}}\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/caee7e0984c83f0919c15ca2ca7b239635247789)