5.5 The Substitution Rule/21: Difference between revisions

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u &= \sqrt{u}
u &= \sqrt{u}
   \\[2ex]
   \\[2ex]
du &= \pi\; dx \\[2ex]
du &= \1/2\; dx \\[2ex]
\frac{1}{\pi}du &= dx
\frac{1}{\pi}du &= dx
\end{align}
\end{align}
</math>
</math>

Revision as of 08:41, 7 September 2022


Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} u &= \sqrt{u} \\[2ex] du &= \1/2\; dx \\[2ex] \frac{1}{\pi}du &= dx \end{align} }