5.5 The Substitution Rule/21: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Line 10: Line 10:
   \\[2ex]
   \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
du &= \frac{1}{2}\ \frac{1}{\sqrt{t}} dx \\[2ex]
\frac{1}{\pi}du &= dx
2du &= dx
\end{align}
\end{align}
</math>
</math>

Revision as of 08:45, 7 September 2022