6.2 Trigonometric Functions: Unit Circle Approach/113: Difference between revisions

Revision as of 23:18, 13 September 2022

$f(x)=\sin(x)$
$g(x)=\cos(x)$
$h(x)=2x$
$p(x)={\frac {x}{2}}$

<math>(p\circ g)(315^{\circ})= \cos(315^{\circ})

Revision as of 23:16, 13 September 2022 (view source) Hannag101602@students.laalliance.org (talk \| contribs) No edit summary ← Older edit		Revision as of 23:18, 13 September 2022 (view source) Hannag101602@students.laalliance.org (talk \| contribs) No edit summary Newer edit →
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	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(p\circ g)(315^{\circ})=~~h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}~~\~~right)=h~~(30^{\circ})~~=2\cdot30^{\circ}=60^{\circ}</math>~~		<math>(p\circ g)(315^{\circ})= \cos(315^{\circ})