6.1 Areas Between Curves/7: Difference between revisions
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(Created page with "<math>f(x)=x</math> <math>g(x)=x^2</math> <math>Pi\int_{a}^{b}\(R-r)dx</math> <math>R=x</math> <math>r=x^2</math> <math>\int_{0}^{1}\(x-x^2)dx</math> <math>\frac{x^2}{2}-\frac{x^3}{3}\bigg|_{0}^{1}</math> <math>\frac{1^2}{2}-\frac{1^3}{3}-\frac{0^2}{2}-\frac{0^3}{3} <math\>\frac{1}{6}/math>") |
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<math>Pi\int_{a}^{b}\(R-r)dx</math> | <math>Pi\int_{a}^{b}\(R-r)dx</math> | ||
<math>R=x</math> <math>r=x^2</math> | <math>R=x</math> | ||
<math>r=x^2</math> | |||
<math>\int_{0}^{1}\(x-x^2)dx</math> | <math>\int_{0}^{1}\(x-x^2)dx</math> | ||
<math>\frac{x^2}{2}-\frac{x^3}{3}\bigg|_{0}^{1}</math> | <math>\frac{x^2}{2}-\frac{x^3}{3}\bigg|_{0}^{1}</math> | ||
<math>\frac{1^2}{2}-\frac{1^3}{3}-\frac{0^2}{2}-\frac{0^3}{3} | <math>\frac{1^2}{2}-\frac{1^3}{3}-\frac{0^2}{2}-\frac{0^3}{3} | ||
<math\>\frac{1}{6}/math> | <math\>\frac{1}{6}/math> |
Revision as of 23:00, 18 September 2022
Failed to parse (syntax error): {\displaystyle Pi\int_{a}^{b}\(R-r)dx}
Failed to parse (syntax error): {\displaystyle \int_{0}^{1}\(x-x^2)dx} <math>\frac{1^2}{2}-\frac{1^3}{3}-\frac{0^2}{2}-\frac{0^3}{3} <math\>\frac{1}{6}/math>