5.4 Indefinite Integrals and the Net Change Theorem/27: Difference between revisions
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&=\left[\frac{2(4)^{3/2}}{3}+\frac{2(4)^{5/2}}{5}\right]-\left[\frac{2(1)^{3/2}}{3}+\frac{2(1)^{5/2}}{5}\right] \\[2ex] | &=\left[\frac{2(4)^{3/2}}{3}+\frac{2(4)^{5/2}}{5}\right]-\left[\frac{2(1)^{3/2}}{3}+\frac{2(1)^{5/2}}{5}\right] \\[2ex] | ||
&=\left[\frac{16}{3}+\frac{64}{5}]-[\frac{2}{3}+\frac{2}{5} \right] | &=\left[\frac{16}{3}+\frac{64}{5}\right]-\left[\frac{2}{3}+\frac{2}{5} \right] \\[2ex] | ||
&=\frac{256}{15} | &=\frac{256}{15} | ||
\end{align} | \end{align} | ||
</math> | </math> |
Revision as of 15:12, 21 September 2022