5.4 Indefinite Integrals and the Net Change Theorem/29: Difference between revisions

Revision as of 15:15, 21 September 2022

$\int _{2}^{-1}\left(4y^{3}+{\frac {2}{y^{3}}}\right)dy=y^{4}-y^{-}2{\bigg |}_{-2}^{-1}=(1-1)-\left(16-{\frac {1}{4}}\right)={\frac {-63}{4}}$

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-<math>\int\limits_{2}^{-1}\left(4y^3+\frac{2}{y^3}\right)dy</math><br>
+<math>
-<math>= y^4-y^-2\bigg|_{-2}^{-1}</math><br>
+\int_{2}^{-1}\left(4y^3+\frac{2}{y^3}\right)dy
-<math>= (1-1)-\left(16-\frac{1}{4}\right)</math><br>
+= y^4-y^-2\bigg|_{-2}^{-1}
-<math>= \frac{-63}{4}
+= (1-1)-\left(16-\frac{1}{4}\right)
+= \frac{-63}{4}
 </math>