5.4 Indefinite Integrals and the Net Change Theorem/37: Difference between revisions

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\end{align}
\end{align}
</math>
</math>
= \int_{0}^{\frac{\pi}{4}}sec^2(\theta)} + 1 \\[2ex]
 
<math>
= \int_{0}^{\frac{\pi}{4}}\sec^2(\theta)} + 1 \\[2ex]
</math>

Revision as of 16:00, 21 September 2022

Failed to parse (syntax error): {\displaystyle = \int_{0}^{\frac{\pi}{4}}\sec^2(\theta)} + 1 \\[2ex] }