Chris: Difference between revisions

Revision as of 17:30, 23 August 2022

Je m'appelle Christopher Sanchez.
$f(x)=2x-3$
$g(x)=x+2$
$(fxg),(f-g),(f+g),({\frac {f}{x}})$

@@ Line 2: / Line 2: @@
 <math>f(x)= 2x-3</math><br>
 <math>g(x)= x+2 </math><br>
-<math> {\frac{f}{x}} </math>
+<math> (fxg),(f-g),(f+g),({\frac{f}{x}}) </math>