5.3 The Fundamental Theorem of Calculus/1: Difference between revisions

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<math>\int\frac{x}{\sqrt{x^2+1}}dx=\sqrt{x^2+1}+c</math>


<math>\frac{d}{dx}(x^2+1)^(\frac{1}{2})+c</math>

Latest revision as of 19:59, 23 August 2022