5.3 The Fundamental Theorem of Calculus/20: Difference between revisions

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$\int _{-2}^{5}6dx=6x{\bigg |}_{-2}^{5}=6(5)-6(-2)=30+12=42$

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	<math>\int_{-2}^{5}6dx = 6x\|_{-2}^{5}</math>		<math>\int_{-2}^{5}6dx = 6x\bigg\|_{-2}^{5}=6(5)-6(-2)=30+12=42</math>