5.4 Indefinite Integrals and the Net Change Theorem/29: Difference between revisions

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<math>\int\limits_{2}^{-1}\left(4y^3+2/y^3\right)dy</math><br>
<math>
<math>y^4-y^-2\bigg|_
\begin{align}
(1-1)-(16-1/4)=-63/4
 
\int_{-2}^{-1}\left(4y^3+\frac{2}{y^3}\right)dy &= \int_{-2}^{-1}\left(4y^3+2y^{-3}\right)dy\\[2ex]
&= \left[y^{4}-y^{-2}\right]_{-2}^{-1} \\[2ex]
&= (1-1)-\left(16-\frac{1}{4}\right) \\[2ex]
&= -\frac{63}{4}
 
\end{align}
</math>
</math>

Latest revision as of 19:40, 21 September 2022