6.2 Trigonometric Functions: Unit Circle Approach/112

$f(x)=\sin(x)$
$g(x)=\cos(x)$
$h(x)=2x$
$p(x)={\frac {x}{2}}$

$(g\circ p)(60^{\circ })=h(p(60^{\circ })=h\left({\frac {60^{\circ }}{2}}\right)=h(30^{\circ })=2\cdot 30^{\circ }=60^{\circ }$