6.2 Trigonometric Functions: Unit Circle Approach/112: Difference between revisions

Latest revision as of 16:24, 7 September 2022

$f(x)=\sin(x)$
$g(x)=\cos(x)$
$h(x)=2x$
$p(x)={\frac {x}{2}}$

$(g\circ p)(60^{\circ })=h(p(60^{\circ })=h\left({\frac {60^{\circ }}{2}}\right)=h(30^{\circ })=2\cdot 30^{\circ }=60^{\circ }$

Revision as of 17:25, 26 August 2022 (view source) Dvaezazizi@laalliance.org (talk \| contribs) No edit summary ← Older edit		Latest revision as of 16:24, 7 September 2022 (view source) Kevind75816@students.laalliance.org (talk \| contribs) No edit summary
(4 intermediate revisions by 2 users not shown)
Line 4:		Line 4:
	<math>p(x)=\frac{x}{2}</math><br><br>		<math>p(x)=\frac{x}{2}</math><br><br>

	<math>(h\circ p)(60^{\circ})</math>		<math>(g\circ p)(60^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>