6.2 Trigonometric Functions: Unit Circle Approach/107: Difference between revisions

Latest revision as of 01:50, 6 September 2022

$f(30)=\sin(30)$
$g(30)=\cos(30)$
$h(x)=2x$
$p(x)={\frac {x}{2}}$

${\frac {1}{2}}$ + ${\frac {\sqrt {3}}{2}}$ = ${\frac {1+{\sqrt {3}}}{2}}$

$(h\circ p)(30^{\circ })=h(p(30^{\circ })=h\left({\frac {30^{\circ }}{2}}\right)=h(15^{\circ })=2\cdot 15^{\circ }=30^{\circ }$

@@ Line 4: / Line 4: @@
 <math>p(x)=\frac{x}{2}</math><br><br>
-<math>(h\circ p)(60^{\circ})=h(p(60^{\circ})=h\left(\frac{60^{\circ}}{2}\right)=h(30^{\circ})=2\cdot30^{\circ}=60^{\circ}</math>
+<math>\frac{1}{2}</math> + <math>\frac{\sqrt3}{2}</math> =
+<math>\frac{1+\sqrt3}{2}</math>
+<math>(h\circ p)(30^{\circ})=h(p(30^{\circ})=h\left(\frac{30^{\circ}}{2}\right)=h(15^{\circ})=2\cdot15^{\circ}=30^{\circ}</math>