5.5 The Substitution Rule/41: Difference between revisions

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<math>
<math>


\int \frac{1}{\sqrt{1-x^{2}} \arcsin {x}} = \int \frac{1}{u} du = \ln |u| +c = \ln |\arcsin {x}| + c
\int \frac{1}{\sqrt{1-x^{2}} \arcsin {x}}  
</math>
</math>


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u &= \arcsin {x}
u &= \arcsin {x}
   \\[2ex]
   \\[2ex]
du &= \frac{1}{\sqrt{1-x^2}} dx \\[2ex]
du &= \frac{1}{\sqrt{1-x^2}}\;dx \\[2ex]


\end{align}
</math>
<math>
\begin{align}
\int (\frac{1}{\sqrt{1-x^{2}}}\frac{1}{\arcsin {x}})\;dx
&= \int \frac{1}{u}\;du \\[2ex]
&= \ln |u| +c \\[2ex]
&= \ln |\arcsin {x}| + c \\[2ex]
\end{align}
\end{align}
</math>
</math>

Latest revision as of 23:19, 13 September 2022