6.1 Areas Between Curves/25: Difference between revisions

From Burton Tech. Points Wiki
Jump to navigation Jump to search
No edit summary
No edit summary
Tag: Manual revert
 
(45 intermediate revisions by the same user not shown)
Line 6: Line 6:
& \color{red}\mathbf{y=x^{2}}  
& \color{red}\mathbf{y=x^{2}}  
& \color{royalblue}\mathbf{y=\frac{2}{({x^2}+1)}} \\
& \color{royalblue}\mathbf{y=\frac{2}{({x^2}+1)}} \\
& x=-1
& x=1


\end{align}
\end{align}
Line 13: Line 15:
\begin{align}
\begin{align}


\int_{1}^{-1}\left(\frac{2}{({x^2}+1)}\right) - \left(x^{2}\right) dx = \int_{1}^{-1}\left(2\cdot\frac{1}{(x^{2}+1)}\right)-\left(x^{2}\right) dx &= \left[(2arctan(x)-\frac{x^{3}}{3})\right]\Bigg|_{-1}^{1} \\[2ex]
\int_{1}^{-1}\left(\frac{2}{{x^2}+1} - x^{2}\right) dx &= \int_{1}^{-1}\left(2\cdot\frac{1}{x^{2}+1}-x^{2}\right) dx \\[2ex]
 
&= \left[2\arctan(x)-\frac{x^{3}}{3}\right]\Bigg|_{-1}^{1} \\[2ex]
 
&= \left[2\arctan(1)-\frac{(1)^{3}}{3}\right]-\left[2\arctan(-1)-\frac{(-1)^{3}}{3}\right] \\[2ex]
 
&= \left[\frac{2\pi}{4}-\frac{1}{3}\right] - \left[-\frac{2\pi}{4}-\left(-\frac{1}{3}\right)\right] \\[2ex]
 
&= \frac{\pi}{2}-\frac{1}{3}+\frac{\pi}{2}-\frac{1}{3} \\[2ex]
 
&= \pi-\frac{2}{3}


\end{align}
\end{align}
</math>
</math>

Latest revision as of 22:45, 26 September 2022

Desmos-graph-25.png