5.3 The Fundamental Theorem of Calculus/1: Difference between revisions

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<math>\int\frac{x}{\sqrt{x^2+1}}dx=\sqrt{x^2+1}+c</math>


<math>\frac{d}{dx}\left[(x^2+1)^\frac{1}{2}+c\right]</math>
let <math>a=x^2+1</math> and <math>b=a^{1/2}</math> then <math>\frac{da}{dx}=2x \text{and} \frac{db}{da}=\frac{1}{2}*a^{-1/2}</math>

Latest revision as of 19:59, 23 August 2022

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